36=2x^2+2x+40

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Solution for 36=2x^2+2x+40 equation: 



36=2x^2+2x+40

We move all terms to the left:

36-(2x^2+2x+40)=0

We get rid of parentheses

-2x^2-2x-40+36=0

We add all the numbers together, and all the variables

-2x^2-2x-4=0

a = -2; b = -2; c = -4;
Δ = b2-4ac
Δ = -22-4·(-2)·(-4)
Δ = -28
Delta is less than zero, so there is no solution for the equation

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